3t+4.9t^2-107=0

Solution for 3t+4.9t^2-107=0 equation:

3t+4.9t^2-107=0

a = 4.9; b = 3; c = -107;
Δ = b2-4ac
Δ = 32-4·4.9·(-107)
Δ = 2106.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{2106.2}}{2*4.9}=\frac{-3-\sqrt{2106.2}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{2106.2}}{2*4.9}=\frac{-3+\sqrt{2106.2}}{9.8}
$